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"Find the center, vertices, and foci of the ellipse with equation 4x^2 + 6y^2 = 24."
So I simplified that down to x^2 + y^2 = 1
So the center must be 0,0 but the vertices at +/- 1 isn't a thing.
I used a graphing calculator and got verticies at +/- 1. But that isn't an answer choice
well, if you simplify it, you'll get: \[\frac{ x^2 }{ 6 } + \frac{ y^2 }{ 4 }=1\]
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True
I did like: 4x^2 + 6y^2 = 24 x^2 + 6y^2 = 24 / 4 x^2 + 6y^2 = 6 x^2 + y^2 = 1
so I see I cant do math.
I know what I did wrong.
yes, the problem lays in the second step: if you had: \[x^2+6y^2=6\] that can't be, because you divided by 4, so you'd have: \[x^2+\frac{ 3y^2 }{ 2 }=6\]
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Yup
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