What is the distance between -4,0 and 5,0?
use the distance formula which is https://www.google.com/url?sa=i&rct=j&q=&esrc=s&source=images&cd=&cad=rja&uact=8&ved=0CAcQjRw&url=http%3A%2F%2Fwww.howe-two.com%2Fteacher%2Fgraphics%2FFormulas_Graphs%2F&ei=RtgWVY_UC5LbsASC34LoCg&bvm=bv.89381419,d.cWc&psig=AFQjCNHCuYwuYKG5mGbVzxkziL7eOjGhjg&ust=1427646905871686
\[\sqrt{(y _{2}-y _{1})^2-(x _{2}-x _{1})^2}\]
use this
Distance formula between two poins P1(x1,y1) P2(x2,y2): \[d(p_1p_2)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
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im extermely sorry :)
it would substitute in as (5+4)^2 + (0-0)^2
\[d(p_1p_2)=\sqrt{(9)^2}\]
the reason why it is (5+4) is because 2 negatives make a positive
example: \[b-(-a)=b+a\]
then (5+4)^2 would be 9^2 and (0-0)^2 would be 0^2
9^2 would turn into 81 and 0^2 would turn into 0
81+0=81
then you will have to find the square root of 81
\[d(p_1p_2)=\sqrt{81}\]
which is 9
so your answer will be 9
\[d(p_1p_2)=9\]
yes correct :) Good luck!!
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