Differential equation help. *Question attached below*
So, I've been working on this problem and I've gotten as far as: \[\frac{ xy }{ x+1} = \frac{- e ^{-x ^{2}} }{ 2 } +C\] Can I have some help please?
thats the end of it.
you may isolate "y" if you want but its not really necessary.. you're done with solving the DE!
Yes, I need to isolate y as the answer includes y isolated
whats stopping you from isolating y ?
I'm stuck at getting the answer I'm supposed to get. The fraction I got up to where I'm stuck is troublesome
you remember along time ago like you were asked to solve equation like this: \[\frac{3}{5} y=4\] and the teacher or whoever was like multiply by the reciprocal of the coefficient of yon both sides that is you would multiply 5/3 on both sides
there is suppose to be a space between y and on
\[\frac{ xy }{ x+1} = \frac{- e ^{-x ^{2}} }{ 2 } +C \\ \frac{x}{x+1} \cdot y=\frac{-e^{-x^2}}{2}+C\]
you have the same type of equation here
@freckles, let me attempt it from there
I got it! Thank you! :D @freckles
np
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