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Mathematics 15 Online
OpenStudy (mathmath333):

geometry question

OpenStudy (mathmath333):

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OpenStudy (mathmath333):

A cone of height '\(h\)' is cut by plane into two parts from the height '\(\dfrac{h}{3}\)' from the base ,and a new small cone and a frustum are formed. Find the ratio of volume of new cone and the frustum.

OpenStudy (mrnood):

first of all write the equation for the volume of a cone I will help further if oyu do that

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}V=\dfrac{\pi r^2h}{3}\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

OK So now look at he tip of the cone - the cut off bit what is its height (compared to the original)?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}h_1=\dfrac{2h}{3}\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

ok now - you can see that the radius of the base of the cut off bit is proportional to the height so what is the radius of the base of the cut off bit

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}r_1=\dfrac{2r}{3}\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

good so now ypou have a small cone with h = 2H/3 and r = 2R/3 so what is the volume of this small cone?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}V_1=\dfrac{\pi}{3}\left(\dfrac{2r}{3}\right)^2\left(\dfrac{2h}{3}\right)\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

so this is 8/27 of the original so what is the volume of the frustrum? (it's what's left when you take away 8/27)

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}V_{frustrum}=\dfrac{\pi}{3}r^2h-\dfrac{\pi}{3}\left(\dfrac{2r}{3}\right)^2\left(\dfrac{2h}{3}\right)\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

YES - but it is easier than that to work out if the tip is pir^2h/3 *(2/3)^3 that is 8/27th of th eoriginal - so how much is left in the frustrum?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}V_{frustrum}=\dfrac{19}{27}\hspace{.33em}\\~\\ \end{align}}\) ?

OpenStudy (mrnood):

that is not quite correct we are talking about ratios 8/27 of the original is in the tip 19/27 of the original is in the frustrum so what is the ratio of tip to frustrum?

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align}\dfrac{V_{new cone}}{V_{frustrum}}=\dfrac{8}{19}\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (mrnood):

correct - well done

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