The radius of a spherical balloon is growing at the rate of 50 cm/s. How quickly is the volume increasing when the radius is 6 cm?
well you know these things \[\frac{dr}{dt} = 50\] you also know \[V = \frac{4}{3} \pi r^3\] so you then need to find the 1st derivative of volume with respect to the radius \[\frac{dV}{dr}\] to find the rate of change in volume with respect to time its \[\frac{dV}{dt}= \frac{dV}{dr} \times \frac{dr}{dt}\] the last task is to substitute r = 6 into dV/dt to find the answer. Hope it helps
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ok... so you haven't studied related rates..?
if you have studied calculus can you find the 1st derivative of the volume, with respect to r. which means finding dV/dr
i dont get it.
so you don't get calculus... or related rates..?
you dont get, anything that campbell is saying? what course is this in?
we want how V chainges with respect to time, so i just do dV/dt implicitly and fill in the rest
i spose %50 is the same regardless of how you approach it :)
*50 ... my fingers hate me
will my answer be 245 pi?
no it's not
can I ask, do you know how to differentiate..?
yes,just confused with the porblem
ok... so make it smaller problems... if \[V = \frac{4}{3} \pi r^3\] can you find \[\frac{dV}{dr}\] or the 1st derivative of the volume with respect to r... ?
so the value \[\frac{4}{3} \pi\] is a coefficient like 5 in 5x so you are really just need to find the derivative of V = r^3
216?
no, that is just substituting r = 6.... the substitution is the last step so I need you to do \[If~~V = r^3~~~what~~is ~~~\frac{dV}{dr} = \]
Where did everybody go?
idk
so any thoughts on what the derivative would be..?
i was out sick for the class-so no not really
here is some information that may help you understand related rates http://tutorial.math.lamar.edu/Classes/CalcI/RelatedRates.aspx https://www.khanacademy.org/math/differential-calculus the notes are worth reading, and the Khan academy stuff contains notes and hopefully some videos... I think you need to understand differentiation before doing this question on related rates... Its about have sound basics... to achieve success
what about this maths problem?
So I'll leave... I'm sure someone will provide you with an answer if the question is left open... But I think you need to do some revision 1st
alright.
Well it appears that knowing how to differentiate is prerequisite for related rates.
If I differentiated for dV/dr do you think you could do the rest of the math?
I just checked out those links provided by campbell_st, they are really good, especially the second one. I believe after watching several videos you will have no problem solving this problem.
i will check it out.
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