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Mathematics 18 Online
OpenStudy (anonymous):

Simplify and write with positive exponents and no radicals.

OpenStudy (anonymous):

\[\sqrt[3]{x ^{7}}/\sqrt{x ^{3}}\] I don't really understand how to move the 3. Any help would be greatly appreciated! :)

OpenStudy (saifoo.khan):

\[\Large \frac{\sqrt[3]{x^7}}{\sqrt{x^3}}\]Like this?

OpenStudy (saifoo.khan):

There's a general rule for radicals. \[\Large \sqrt[a]{x^b} = x^\frac ba\]

OpenStudy (anonymous):

yes like that. and ok so it would be \[x^{7/3}/\sqrt{x^{3}}\] not quite sure where to go from there

OpenStudy (saifoo.khan):

Yes. You're right. In the denominator change it in this form as well. It will look something like: \[\Large \frac{x^\frac73}{x^\frac32}\] Agree?

OpenStudy (anonymous):

Where did the 2 come from? Is it because you squared the sqrt?

OpenStudy (saifoo.khan):

Square root basically means it is to the power 2. \[\Large \sqrt x = \sqrt[2]x = x^\frac12\]

OpenStudy (anonymous):

Then you find a common bottom number? (sorry cant remember the name) so it would be x^14/6 / x^9/6 right? Then subtract and you get x^5/6?

OpenStudy (saifoo.khan):

Then it will be done like this: \[\Large x^{\frac73-\frac32}\]

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