Simplify and write with positive exponents and no radicals.
\[\sqrt[3]{x ^{7}}/\sqrt{x ^{3}}\] I don't really understand how to move the 3. Any help would be greatly appreciated! :)
\[\Large \frac{\sqrt[3]{x^7}}{\sqrt{x^3}}\]Like this?
There's a general rule for radicals. \[\Large \sqrt[a]{x^b} = x^\frac ba\]
yes like that. and ok so it would be \[x^{7/3}/\sqrt{x^{3}}\] not quite sure where to go from there
Yes. You're right. In the denominator change it in this form as well. It will look something like: \[\Large \frac{x^\frac73}{x^\frac32}\] Agree?
Where did the 2 come from? Is it because you squared the sqrt?
Square root basically means it is to the power 2. \[\Large \sqrt x = \sqrt[2]x = x^\frac12\]
Then you find a common bottom number? (sorry cant remember the name) so it would be x^14/6 / x^9/6 right? Then subtract and you get x^5/6?
Then it will be done like this: \[\Large x^{\frac73-\frac32}\]
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