when the plan had flown 4,150 feet from the airport where it had taken off, it had covered a horizontal distance of 3,360 feet. what is the angle at which the plane rose from the ground to the nearest degree?
if you do the drawing, you'll get something like this |dw:1427580922688:dw|
A = airport P = plane
does that make sense?
yes so what would i do next
in reference to angle x, we have the adjacent and hypotenuse as the known sides |dw:1427581068287:dw|
which trig function uses adjacent and hypotenuse together?
cos
yep
cos(angle) = adjacent/hypotenuse cos(x) = 3360/4150
what is the next step to isolating x?
divide the 3360 by 4150?
what do you get
0.80963855421
so if cos(x) = 0.8096 roughly, then what is the approximate value of x?
would i plug that number in for x
no
have you learned about inverse cosine? or arccosine?
like a year ago i basically forget it all! and this is a worksheet i am trying to help my little brother with
the idea of the inverse cosine is to undo cosine so for example, if you plug in x = 1 into cos(x), you'll get some number as a result then if you take that same number and plug it into arccos(x), you'll get the result of 1 back. So the arccos takes you back to the original input
cos(x) = 0.8096 arccos( cos(x) ) = arccos(0.8096) ... apply arccos to both sides x = arccos(0.8096) x = ??
Basically, if the cosine of 10 degrees = 0.98481 Then the arc cosine of 0.98481 = 10 degrees (Hope I'm not confusing things by tossing in this extra information).
I'm taking advantage of the rule arccos(cos(x)) = x where x is some angle in degrees such that \(\Large 0 < x < 90\)
i got 0.99 which i still dont think is correct
what kind of calculator do you have?
its a scientific calculator i just think i plugging in numbers in the wrong places
do you have an arccos function on it? or a \(\large \cos^{-1}\) button?
cos-1
push the \(\large \cos^{-1}\) then type in 0.8096 and hit enter
i got 35.9 which would round to 36
yep 36 degrees roughly
okay thank you for all the help
you're welcome
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