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How much heat is evolved if 25.00 g of methanol (CH3OH) is burned in excess O2? The reaction is: 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(g) ΔH= -1453kJ
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say that only 1 mole of Methanol was burned then the Delta H = -1453/2 so if we burn 25g of methanol and we convert grams of methanol to moles of methanol it is 25gmethanol/32gmethanol = .78125 so we multiprly .78125(-1453/2)
Does this explanation make sense?
Yes it makes more sense now
Is the answer -567.578 kJ?
ya
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thanks dude can you help me with some more?
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