A proper unbiased coin was tossed 10 times for 3 trials, giving TTHHTHTTHH, TTTTTHHHHH, and THTHHTHTTH (T = Tails; H = Heads). What is the difference between the theoretical and experimental probabilities of getting heads? a 0.0 b 0.1 c 0.3 d 0.5
Trial 1: TTHHTHTTHH how many heads are in that sequence above?
5
out of 10 tosses total, so the experimental probability of getting heads is 5/10 = 1/2
repeat the same steps for trial 2: TTTTTHHHHH
15 heads for all trials
d would be correct?
there are 5 heads in TTTTTHHHHH out of 10 tosses so again, experimental probability of getting heads is 5/10 = 1/2
trial 3: THTHHTHTTH experimental probability of getting heads is equal to what?
1/2
yep since again there are 5 heads out of 10 tosses
each time we got 1/2 theoretically, the probability of getting heads is 1/2 because there are 2 outcomes (heads or tails) and 1 of those outcomes is heads
so in this case, the difference is 0 (ie there is no difference). Usually the experimental probability will be a bit off from the theoretical probability
Okay I understand. I wasn't sure what theoretical probability meant. So the answer would be a.
experimental probability is the probability you record after doing an experiment (or multiple experiments) theoretical probability is based off the idea that each side has an equal chance of popping up (this is something you can do without doing experiments)
Thank you for helping.
another way to do this: experimental probability of heads = 15/30 (since there are 15 heads out of a total of 30 tosses). theoretical probability of heads = 1/2 now subtract the two fractions
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