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OpenStudy (anonymous):
a solution containing 100.0 mL of 0.135 M CH3COOH (ka=1.8E-5) is being titrated with 0.54 M NaOH. calculate the ph: at the equivalence point and 5 mL past the equivalence point. how much is 5 mL past? i do not know how to do it?
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OpenStudy (cuanchi):
25mL of NaOH is the equivalence point, then 30mL of NaOH will be 5mL past the equivalence point
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