Question

Lara tossed a fair coin 3 times. What is the probability of getting heads in the first two trials?

1 over 8
2 over 8
3 over 8
4 over 8

Answer 1

@paki

Answer 2

@mayankdevnani @sleepyjess

Answer 3

I think D

Answer 4

@77777jeannie77777 can you made events ?
i mean HHH, TTT etc,

Answer 5

I'm not really sure how to do that :(

Answer 6

make events

Answer 7

1) HHH
2) HHT
3) HTH
4) THH
5) HTT
6) THT
7) TTH
8) TTT

\[\large \bf total~no.~of~trials=2^3=8\]

Answer 8

now, you have to choose that trials or events in which first two trials you get head :-
1) HHH
2) HHT
only 2

Answer 9

so
\[\large \bf P(E)=\frac{no.of~trials}{Total~no.of~outcomes}=\frac{2}{8}=\frac{1}{4}\]

Answer 10

oh so then its 1/2 probability?

Answer 11

hope you understand. @77777jeannie77777

Answer 12

no @77777jeannie77777
you have to calculate :- `probability of getting heads in the first two trials`

Answer 13

understood?? @77777jeannie77777

Answer 14

hmm..... wait a sec plz lemme see

Answer 15

:)

Answer 16

OH so then its umm 1/4 probability??

Answer 17

correct !

Answer 18

If its that then the answer is B, right??

Answer 19

right !

Answer 20

@mayankdevnani ??

Answer 21

you are right !

Answer 22

@77777jeannie77777 ??
lol

Answer 23

lol sorry thx :):)