What is the maximum amount of Li2CO3 that can form when 3.13 mol of CO2 reacts with excess LiOH?
CO2+2LiOH yields Li2CO3+H2O

A. 1.565 mol B. 3.13 mol
C. 6.26 mol D. 12.52 mol

Question

What is the maximum amount of Li2CO3 that can form when 3.13 mol of CO2 reacts with excess LiOH?
              CO2+2LiOH yields Li2CO3+H2O

A. 1.565 mol       B. 3.13 mol
C. 6.26 mol         D. 12.52 mol

anonymous · Answer

I couldnt figure it out. It's confusing me. I was out of school for 4 days due to the stomach virus.

sleepyjess · Answer

Welcome to OpenStudy! This should probably go in the $\href{http:///openstudy.com/study#/groups/Chemistry}{\sf Chemistry}$ section :)

anonymous · Answer

Theres no one there to help. And i really need it done.

sleepyjess · Answer

@asnaseer ?

anonymous · Answer

Mol ratio is 1:1
From looking at the balanced equation, for every 1 mol of CO2, we produce 1 mol Li2CO3.  

Stoichiometry 
$$\frac{ 3.13 mol CO2 }{  } \times \frac{ 1 mol Li2CO3 }{1 mol CO2  } = 3.13 mol Li2CO3$$

I suggest you use stoichiometry every time you these problems, as it gets complicated later if you need to get mols to grams to molarity and so forth.