Question

Write a formula for the nth term of the sequence

7, 10, 13, 16

Answer 1

There are infinitely many such formulas. What sort would you like?

IF the question had said "arithmetic sequence", THEN there would be a unique answer. The question didn't say that.

Literally, write ANY nth term you can justify.

n = 1 Term = 7
n = 2 Term = 10
n = 3 Term = 13
n = 4 Term = 16

Someone might point out that there seems to be a common difference of three so it MUST BE an arithmetic sequence with common difference of 3. You are free to assume this, but it is NOT the only solution.

10-7 = 3
13-10 = 3
16-13 = 3

n = 1 Term = 7
n = 2 Term = 10 = 7 + 3
n = 3 Term = 13 = 10 + 3
n = 4 Term = 16 = 13 + 3

n = 1 Term = 7
n = 2 Term = 10 = 7 + 3
n = 3 Term = 13 = 7 + 2*3
n = 4 Term = 16 = 7 + 3*3

I'm seeing one possible pattern. There are MANY others.

Answer 2

Yes I know and this is an arithmetic series, the distance is 3, and so on...

Answer 3

I'm not sure though, but would the answer be like an= 3n +4????

Answer 4

Who said it was an Arithmetic Sequence? Did you fail to report this as part of the problem statement? It is a VERY important piece of information.

Answer 5

How is it not Arithmetic?

Answer 6

ok nvm, but what's the answer, I get this stuff, I just need an answer

Answer 7

ok well is this the answer, yes or no?
an= 3n +4?

Answer 8

tkhunny you the best

Answer 9

guys, please i'm about to cry, just is this the answer yes or no?
an= 3n +4

or would this be the answer?

an = 7 +3 (n-1)? yes or no

which one is it? or none of the above????

Answer 10

You do not get this stuff if you have argued what you just said. Try this function:

\(f(x) = (1/6)(x^{3} - 6x^{2} + 29x + 18)\)

Evaluate it for x = 1, x = 2, x = 3, and x = 4. Use synthetic division if you like.

Then you tell me, "How can it not be arithmetic."

Answer 11

hey I gtg, just please, just tell me the answer,
if not you then somebody, please
all i want is the answer PLEASE

Answer 12

You already created two correct answers. I gave you a third.