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Mathematics 9 Online
OpenStudy (jpes2193):

How would I find..... see comments

OpenStudy (jpes2193):

\[\log_{7}42= \]

OpenStudy (michele_laino):

we can simplify your expression as follows: \[\log _{7}42=\log _{7}7+\log _{7}6=1+\log _{7}6\]

OpenStudy (jpes2193):

Ok and that should give you the same answer as the change of base formula?

OpenStudy (michele_laino):

yes I think so, since even if we change the base, the final result has to be the same

OpenStudy (jpes2193):

okay so i would subtract the log7(6) and get log7(7)=1 then what?

OpenStudy (michele_laino):

in order to get the result of your expression, we can compute log_7(6) using, for example, Windows calculator

OpenStudy (jpes2193):

oh ok

OpenStudy (michele_laino):

sorry, we have to change the base of our logarithm from 7 to 10, first

OpenStudy (jpes2193):

ahh see thats where you lost me. so Ill just stick with the change of base formula for this test...

OpenStudy (michele_laino):

in order to that, we can apply the subsequent formula: \[{\log _{10}}6 = \frac{{{{\log }_7}6}}{{{{\log }_7}10}}\]

OpenStudy (michele_laino):

sorry I gave you the wrong formula, here is the right formula:

OpenStudy (michele_laino):

\[{\log _7}6 = \frac{{{{\log }_{10}}6}}{{{{\log }_{10}}7}}\]

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