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Chemistry 5 Online
OpenStudy (vera_ewing):

What fills the space between cations in the model that describes metals? A. the nucleus B. electrons C. protons D. neutrons

OpenStudy (vera_ewing):

OpenStudy (anonymous):

B. In metals, the metallic bond consists in positive ions being surrounded by delocalized electrons.

OpenStudy (vera_ewing):

thanks!

OpenStudy (vera_ewing):

Which formula is possible for a compound with the following mass ratios? Element % Carbon 40.0 Hydrogen 6.70 Oxygen 53.3 A. C2HO2 B. CH2O C. C2HO D. CHO2

OpenStudy (vera_ewing):

Do you know the answer? @Hoslos

OpenStudy (anonymous):

First of all, recall to use the formula n=m/Mr, where n is moles, m is given mass and Mr is molecular mass. When it comes to percentage, consider them as the given mass. Let us work for each element. Carbon - finding n=m/Mr= 40/12=3.3mol Hydrogen - n=m/Mr= 6.70/2= 3.35mol Oxygen - n=m/Mr= 53.3/32=1.67 mol As for the second step, look for the smallest value among the number of moles and didvide all the previous calculated values by the smallest one. In this case, the smallest one is 1.67. For Carbon will be 3.3/1.67= approximately 2 mol For Hydrogen will be 3.35/1.67= 2 mol For Oxygen will be 1.67/1.67= 1 mol Finally the formula is C2H2O. Are you sure you copied well the answers?

OpenStudy (vera_ewing):

A. \[C_{2}HO _{2} \] B. \[CH _{2}O\] C. \[C _{2}HO\] D. \[CHO _{2}\]

OpenStudy (anonymous):

My mistake. For Hydrogen in the forst step it should have been 6.7/1= 6.7 and for Oxygen 53.3/16= 3.3 The smallest number is then 3.3 For the second step it will be 3.3/3.3= 1 for C 6.7/3.3= 2 for H 3.3/3.3= 1 for O The formula shall then be CH2O.

OpenStudy (vera_ewing):

Thanks! The balanced net ionic equation resulting from addition of aqueous hydrochloric acid to solid chromium(III) hydroxide is: A. Cr(OH)3 (s) + 3 Cl- (aq) ---> 3 OH- (l) + CrCl3 (aq) B. Cr(OH)3 (s) + 3 HCl (aq) ---> 3 H2O (l) + CrCl3 (aq) C. Cr(OH)3 (s) + 3 H+ (aq) + 3 Cl- (aq) ---> 3 H2O (l) + Cr3+(aq) + 3 Cl- (aq) D. Cr(OH)3 (s) + 3 H+(aq) + 3 Cl- (aq) ---> 3 H2O (l) + CrCl3 (s) E. Cr(OH)3 (s) + 3 H+(aq) ---> 3 H2O(l) + Cr3+(aq)

OpenStudy (anonymous):

when HCl ionizes, it formes H+ and Cl-. The H+ is capable enough to replace Cr from its compound and the Cl- will bind with the Cr replaced. Hence I believe the answer is D.

OpenStudy (vera_ewing):

It was actually E but that's ok :)

OpenStudy (anonymous):

Oh, yes, since they want an ionic equation it becomes E, which is almost the same as D, but the difference is that E has ions.

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