Question

Can someone please help me I have to prove this equation is true using algebraic proof, identifying each step, and demonstrate that it works on numerical relationships. The equation is
(x-y)(x-y)=x^2-xy-yx+y. All I have so far is
(2-3)(2-3)=2^2-2x3-3x2+3. Help would be most appreciated.

Answer 1

(x-y)(x-y)=x^2-2(xy)+y^2 would be the correct way. you could show that using the distributive property and it would explain it (the distributive property is when you multiply all variables or terms within a set of parentheses by a constant, variable, or all terms in another set of parentheses).

Answer 2

multiply (second bracket ) by each TERM in the( first bracket)
x*x +x*(-y) then -y *x +(-y)*(-y)
x^2 -xy -xy +y^2 because miinus times minus gives positive
I notice you did not have y^2 in your question a typo??
so not 3 but 3^2 =9
so you have 4-6-6+9=1
(2-3)(2-3)
(-1)(-1) =+1 as your proof