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It takes 250.0 J to raise the temperature of a 50.0 g sample of a metal by 10.0C. What is the specific heat capacity of this metal? A. 1.25 x 105 J/g K B. 5.00 x 10-4 J/g K C. 50.0 J/g K D. 1.25 x 102 kJ/g K E. 0.500 J/g K
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@sweetburger please help!
q=MC Delta T
so 250J =q 50g = m and 10C is equal to Delta T
250J = 50g(C)(10C) = 250/(500) = 1/2 or .5
So what would the answer be?
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E?
yes
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