Mathematics
8 Online
OpenStudy (anonymous):
what is the value of x? rounded to the nearest tenth.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@bibby
jimthompson5910 (jim_thompson5910):
Use the pythagorean theorem to get...
a^2 + b^2 = c^2
x^2 + 16^2 = 19^2
x^2 + 256 = 361
x = ???
I'll let you finish up
OpenStudy (anonymous):
11,025
jimthompson5910 (jim_thompson5910):
how are you getting that result?
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OpenStudy (anonymous):
256 - 361=-105 x -105 and i got that answer
jimthompson5910 (jim_thompson5910):
x^2 + 256 = 361
x^2 + 256-256 = 361-256
x^2 = 105
x = ???
note: you do NOT square 105 to get 11,025
OpenStudy (anonymous):
so x is 105
jimthompson5910 (jim_thompson5910):
x squared is 105
x itself isn't 105
OpenStudy (anonymous):
i have to find the square root of 105?
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jimthompson5910 (jim_thompson5910):
the exact answer is \[\Large x = \sqrt{105}\]
jimthompson5910 (jim_thompson5910):
and it cannot be simplified
OpenStudy (anonymous):
i square rooted it and i got 10.24
jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{105} \approx 10.24695\]
so the approximate answer is
\[\Large x \approx 10.24695\]
don't forget to round that to the nearest tenth
OpenStudy (anonymous):
rounded would be 10.2 right?
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jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
thanks can you help me with a few more?
jimthompson5910 (jim_thompson5910):
I can help with one more
OpenStudy (anonymous):
okay thanks ill tag you