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Mathematics 8 Online
OpenStudy (anonymous):

what is the value of x? rounded to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (anonymous):

@bibby

jimthompson5910 (jim_thompson5910):

Use the pythagorean theorem to get... a^2 + b^2 = c^2 x^2 + 16^2 = 19^2 x^2 + 256 = 361 x = ??? I'll let you finish up

OpenStudy (anonymous):

11,025

jimthompson5910 (jim_thompson5910):

how are you getting that result?

OpenStudy (anonymous):

256 - 361=-105 x -105 and i got that answer

jimthompson5910 (jim_thompson5910):

x^2 + 256 = 361 x^2 + 256-256 = 361-256 x^2 = 105 x = ??? note: you do NOT square 105 to get 11,025

OpenStudy (anonymous):

so x is 105

jimthompson5910 (jim_thompson5910):

x squared is 105 x itself isn't 105

OpenStudy (anonymous):

i have to find the square root of 105?

jimthompson5910 (jim_thompson5910):

the exact answer is \[\Large x = \sqrt{105}\]

jimthompson5910 (jim_thompson5910):

and it cannot be simplified

OpenStudy (anonymous):

i square rooted it and i got 10.24

jimthompson5910 (jim_thompson5910):

\[\Large \sqrt{105} \approx 10.24695\] so the approximate answer is \[\Large x \approx 10.24695\] don't forget to round that to the nearest tenth

OpenStudy (anonymous):

rounded would be 10.2 right?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

thanks can you help me with a few more?

jimthompson5910 (jim_thompson5910):

I can help with one more

OpenStudy (anonymous):

okay thanks ill tag you

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