Question

Eli has 7 black pens and 6 blue pens in his desk drawer. He also has 4 yellow highlighters, 2 green highlighters, and 3 pink highlighters in his pencil case. If he chooses one pen and one highlighter without looking, what is the probability that he will get a blue pen and he will not get a pink highlighter?

Answer 1

The number of black pens is 7
the odds of getting a black pen is 7/12

The number of non-green highlighters is 8
the odds of getting a non-green highlighter is...?

Answer 2

6 out of 13 pens and 3 out of 5 for the highlighters i think .

Answer 3

46% if that is a choice because 7/12(pen) times 8/10(Highlighter).

Answer 4

I'm looking for blue pens

Answer 5

and how did you get 8/10?

Answer 6

sorry i read the problem wrong. I guess i cant help but i tried.

Answer 7

oh.... okay

Answer 8

@iGreen

Answer 9

6 out of 13 pens and 3 out of 5 for the highlighters i think .
@BloomLocke367

Answer 10

do I add 6/13 and 6/9 or do I mulitply? and how did you get 3/5?

Answer 11

because if I multiply I get 4/13... and I THINK that's right, but I'm not sure.

Answer 12

nobody worry @iGreen is here

Answer 13

haha cx

Answer 14

well um... I think I'm going to go with that.

Answer 15

Go with what?

Answer 16

Probability of picking a blue pen:

6/13

Probability of not picking a pink highlighter:

6/9

Multiply:

4/13

Yep, you got it.