Fan and medal! Find DG
@iGreen A.12 cm B.6.5 cm C.9 cm D.8 cm
D, G, F act as ABC in this one i presume I think its safe to assume E=10 same as F and would D=...3?
Hi, This is just a suggestion. Since triangle DGF forms a right triangle, why don't you use the Pythagorean theorem to solve for DG? and yes, it's right to assume that ED is equal to 10 (:
im having a hard time setting this one up
im in a remedial math class for a reason i guess XD
im good at solving just not setting up
Pythagorean theorem is \(\sf hypotenuse^2=adjacent^2+opposite^2\) so in this case \(\sf DF^2= GF^2 + DG^2\) you are solving for DG, so it will be like: \(\sf DG^2= DF^2- GF^2 \) just plug in your given values and evaluate the formula (:
DG=? DF=10^2 GF=6^2
yes, like that. removing the square of DG, you have to take the square root of both sides. So it will be like this: \(\sf DG= \sqrt{DF^2- GF^2}\)
10^2 - 6^2 is equal to..?
100 and 36
any confusions? don't hesitate to ask (:
yes, then subtract them
100-36=64 and the square root of that is 8
so....DG=8?
correct (:
awesome thanks so much!
no problem ! ^_^
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