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Mathematics 11 Online
OpenStudy (anonymous):

Fan and medal! Find DG

OpenStudy (anonymous):

@iGreen A.12 cm B.6.5 cm C.9 cm D.8 cm

OpenStudy (anonymous):

D, G, F act as ABC in this one i presume I think its safe to assume E=10 same as F and would D=...3?

OpenStudy (anonymous):

Hi, This is just a suggestion. Since triangle DGF forms a right triangle, why don't you use the Pythagorean theorem to solve for DG? and yes, it's right to assume that ED is equal to 10 (:

OpenStudy (anonymous):

im having a hard time setting this one up

OpenStudy (anonymous):

im in a remedial math class for a reason i guess XD

OpenStudy (anonymous):

im good at solving just not setting up

OpenStudy (anonymous):

Pythagorean theorem is \(\sf hypotenuse^2=adjacent^2+opposite^2\) so in this case \(\sf DF^2= GF^2 + DG^2\) you are solving for DG, so it will be like: \(\sf DG^2= DF^2- GF^2 \) just plug in your given values and evaluate the formula (:

OpenStudy (anonymous):

DG=? DF=10^2 GF=6^2

OpenStudy (anonymous):

yes, like that. removing the square of DG, you have to take the square root of both sides. So it will be like this: \(\sf DG= \sqrt{DF^2- GF^2}\)

OpenStudy (anonymous):

10^2 - 6^2 is equal to..?

OpenStudy (anonymous):

100 and 36

OpenStudy (anonymous):

any confusions? don't hesitate to ask (:

OpenStudy (anonymous):

yes, then subtract them

OpenStudy (anonymous):

100-36=64 and the square root of that is 8

OpenStudy (anonymous):

so....DG=8?

OpenStudy (anonymous):

correct (:

OpenStudy (anonymous):

awesome thanks so much!

OpenStudy (anonymous):

no problem ! ^_^

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