Mathematics
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OpenStudy (anonymous):
If (82)p = 84, what is the value of p?
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OpenStudy (anonymous):
Divide both the sides by \(82\) to find \(p\)..
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
No ok.. Just do it and show me what you did actually..
OpenStudy (anonymous):
2? dont you mean subtract?
OpenStudy (anonymous):
No, I mean divide..
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OpenStudy (anonymous):
1.024.. if i divide
OpenStudy (anonymous):
If (8^2)p = 84, what is the value of p? nevermind this is the problem sorry
OpenStudy (anonymous):
i just looked at it
OpenStudy (anonymous):
Oh..
OpenStudy (anonymous):
sorry
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OpenStudy (anonymous):
@NightCrawlers_
OpenStudy (anonymous):
Tell me :
\(8^2 = ??\)
OpenStudy (nightcrawlers_):
She looks like she got this ^
OpenStudy (anonymous):
She? Who is she here?
OpenStudy (nightcrawlers_):
Oh he?
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OpenStudy (anonymous):
ok back to the question
OpenStudy (anonymous):
Who is he here now?
OpenStudy (anonymous):
\[(8^{2})^{p}=84\]
OpenStudy (anonymous):
thats the question
OpenStudy (anonymous):
Hey man..!! First write your question properly.
Is that fine now? Is that now a right question?
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OpenStudy (anonymous):
p= A2 B3 C4 D6
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
your question is still wrong..
OpenStudy (anonymous):
what do you mean
OpenStudy (anonymous):
It must be then:
\[(8^2)^p = 8^4\]
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OpenStudy (anonymous):
Otherwise, you won't get integer value for \(p\)..
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
but how would i work this out?
OpenStudy (anonymous):
See, when bases are same, exponents are equal.
OpenStudy (anonymous):
\[(a)^b = (a)^c \implies b = c\]
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OpenStudy (anonymous):
p=2 then?
OpenStudy (anonymous):
Good.. Have you guessed it?
OpenStudy (anonymous):
yes sadly
OpenStudy (anonymous):
i wanna know how i did it or how to do it
OpenStudy (anonymous):
See, you need to just make the base look equal on both the sides..
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OpenStudy (anonymous):
For that, look here, we have one power rule property:
\[(a^b)^c = (a)^{b \times c}\]
OpenStudy (anonymous):
Now using it can I write :
\[(8)^4 = (8)^{2 \times 2} \implies (8^2)^2\]
See, this it is just a crystal clear use of that property..
OpenStudy (anonymous):
\[(8^{2})^{2}=8^{4} so then 8^{2} x ^{2}=8^{4}\]
OpenStudy (anonymous):
That is not \(x^2\), but there should be \(8^2\) instead of that..
OpenStudy (anonymous):
what i just wrote but better haha
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OpenStudy (anonymous):
x=multiply
OpenStudy (anonymous):
p=2
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
You can write it the best way as:
\[(8^{2})^{2}=8^{4} \quad \text{so then} \quad 8^{2} \times 8 ^{2}=8^{4}\]
OpenStudy (anonymous):
ok thanks
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OpenStudy (anonymous):
\(\dagger\)