Question

help!!

The function ƒ(x) = x2 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an inverse function.

Answer 1

@CGGURUMANJUNATH hey you have helped me before! could you explain this to me?

Answer 2

@iGreen any ideas?

Answer 3

Limit the domain to x ≥ 0.

Inverse: standard procedure is to replace f(x) on the left by x, replace x by f^(-1) on the right, and solve for f^(-1):

x = (f^(-1))² + a
x - a = (f^(-1))²

Recall that we have limited the domain of f (which is the range of f^(-1)) to non-negative argument; hence, we want the positive square root:

√(x - a) = f^(-1)

Source : https://answers.yahoo.com/question/index?qid=20130730072233AAzEAki

Answer 4

refresh page if comment shows up as symbols //

Answer 5

thank you! but they arent actually the same problems. :(