@FSU i need u again
ok lol what is it but i dont got much time
i gtg but ill help u tommorow if u still need help
hey there! What do you need help with?
Solve the following system of equations using elimination: 4x - 2y = 8 3x - 9y = -54 A. (-3, 5) B. (0, -4) C. (2, 0) D. (6, 8)
OMg i love these
really
yep :) first you want to make is so that the top is positive and the bottom is negative we are talking about the X value
ok
multiply by -3 \[-3(4x - 2y = 8 )\] multiply by 4 \[4(3x - 9y = -54)\]
that what i got
then you are doing it right :) now solve the 2 equations and tell me what u get
i got the the wrong answer know it i got 5
equation 1\[-12x+6=-24\]equation 2 \[12x-36y= -216\]
the 12x will cancel out
so what step do i do first
OK well we distributed the numbers in both of the equations do you get that part?
i really am confused about this kind of math i dont get it
ok is there anything in particular you dont get?
all of it i honestly dont get it
ok elimination is basically in the name you will eliminate opposites so a negative over a positive will cancel out in this case if you do 12 +(-12) you get 0 that leaves you with only the Y value do you get it?
no really?
is it 0 and -4
u there
hellooooooo
no lets get you to understand this first....we have our equations: \[4x - 2y = 8 \]\[3x - 9y = -54 \] to get the opposite number (opposite meaning a negative version and a positive version of the same number so that they cancel out) if we multiply the top by -3 we will get -12 if we multiply the bottom by 4 we will get a positive 12 distribute \[−3(4x−2y=8)\ \[4(3x−9y=−54)\] now when you distribute you get these new equations that look like this:\[−12x+6=−24 \] \[12x−36y=−216 \]
i see it
ok let me know if you dont understand
i dont understand this
What dont you get?
i dont get this
at all
@Data_LG2
@sleepyjess @amistre64
are we still doing Solve the following system of equations using elimination: 4x - 2y = 8 3x - 9y = -54 A. (-3, 5) B. (0, -4) C. (2, 0) D. (6, 8)
yea they dont get it
Okay, first off, do you know how to use the elimination method?
not really
@stacy888
Elimination method is when you ELIMINATE one variable in order to solve for another variable. So for example we have: \(\sf x+ 2y =3 \\ 2x+3y = 4\) we will eliminate the variable "X" by multiplying a number to one of the equations. so in order to eliminate 'x' we have to multiply the first equation by -2. |dw:1427743827445:dw|
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