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Mathematics 19 Online
OpenStudy (anonymous):

given this vectorial space V=< (0, 0, 0, 1), (0, 0, 1, 2), (1, 2, 3, 4)> what value does "a" needs to have so that v=(a,2,4,7). belongs to V

OpenStudy (anonymous):

@Micah1mcdugle

OpenStudy (amistre64):

do you know what an rref is?

OpenStudy (anonymous):

no :/

OpenStudy (amistre64):

it is the augmented matrix (A:b) which results in the solution for of (I:x)

OpenStudy (anonymous):

wow im sorry pay attention

OpenStudy (anonymous):

well now im confused u.u

OpenStudy (anonymous):

im paying attention to im mean

OpenStudy (anonymous):

pardon?

OpenStudy (anonymous):

sorry im confused but I was working on something similar too. sorry

OpenStudy (amistre64):

we can work it up as: 1 0 0 a 2 0 0 2 3 1 0 4 4 2 1 7 and reduce the row echelon form to solve for a

OpenStudy (anonymous):

why are you using the 1 2 3 4 first?

OpenStudy (amistre64):

no particular reason, was easier for these old brain to remember first i spose

OpenStudy (rational):

because the order in which you put the vectors doesn't matter for column space ``` 1 0 0 a 2 0 0 2 3 1 0 4 4 2 1 7 ```

OpenStudy (amistre64):

youre welcome

OpenStudy (rational):

there is a shortcut/eyeballing thing here if we're careful.. Notice that we have only one line (1,2) in the plane represented by first two components `1 0 0` `2 0 0` 3 1 0 4 2 1 so you can only reach the points on this line in the plane represented by first two components

OpenStudy (rational):

\[\large \dfrac{1}{2} = \dfrac{a}{2}\] you can solve \(a\)

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