Use the quadratic formula to solve the equation -2x^2+9x+3=0 a. 9+sqrt105/4 b. 9+sqrt52/2 c. 9+sqrt105/2 d. 4+sqrt210/18 <--- am i right
No, that's not correct. What did you use as your values of a, b, and c?
a=2 b=9 c=3
In the problem statement you wrote that a = -2. So I found the values for a = -2.
ok..
yea it is -2
@mathteacher1729
Ok, so you'll have to re-do your work and check again, this time let a = -2. :)
I have to get dinner now, good luck, I will try to sign on later to check in.
k thanks
\(\bf \textit{quadratic formula}\\ {\color{blue}{ -2}}x^2{\color{red}{ +9}}x{\color{green}{ +3}}=0 \qquad \qquad x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\) solve for "x"
yea i did that and i got 19 for the denominator
i mean 18 sorry
and the numerator 81-24=57
hmmm
19 for the denominator?
how.. did you get 19 anyway for the denominator?
i meant 18
well.. what's "a"?
-2
so... "2a" would be?
oh i wasnt thinking. i thought the denominator was 2b my bad
2X-2=-4
yeap thus \(\bf \textit{quadratic formula}\\ {\color{blue}{ -2}}x^2{\color{red}{ +9}}x{\color{green}{ +3}}=0 \qquad \qquad x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}} \\ \quad \\ x= \cfrac{ - {\color{red}{ 9}} \pm \sqrt { {\color{red}{ 9}}^2 -4{\color{blue}{ (-2)}}{\color{green}{ (3)}}}}{2{\color{blue}{ (-2)}}}\implies x=\cfrac{-9\pm\sqrt{81+24}}{-4}\)
so... what would you end up in the numerator?
ok the answer is a
dunno... what did you get on the numerator?
105 as the sqrt
yeap thus \(\bf x= \cfrac{ - {\color{red}{ 9}} \pm \sqrt { {\color{red}{ 9}}^2 -4{\color{blue}{ (-2)}}{\color{green}{ (3)}}}}{2{\color{blue}{ (-2)}}}\implies x=\cfrac{-9\pm\sqrt{81+24}}{-4} \\ \quad \\ x=\cfrac{-9\pm\sqrt{105}}{-4}\implies x=\cfrac{9\mp\sqrt{105}}{4} \)
thanks
yw
Join our real-time social learning platform and learn together with your friends!