Question

Differential equations - separable
dy/dx=(1+lnx)y and if y=1 when x=1, then y=?

Answer 1

when I separate them I get
dy/y=(1+lnx)dx
I don't know how to integrate the right side

Answer 2

As separate if want

Answer 3

not sure I understand your statement

Answer 4

As. Separate equation

Answer 5

Lorry my tablet is not responding well

Answer 6

that's ok, I am on my ipad. I am having issues as well

Answer 7

what is the Q for? Boy is this website different

Answer 8

\[\frac{ 1 }{y }dy = \left( 1 + lnx \right)dx = dx + lnx dx\]

so integrating both sides

\[\int\limits_{}^{}\frac{ dy}{ y } = \int\limits_{}^{}dx +\int\limits_{}^{}\ln(x)dx\]

u can continue from here. good luck :)

Answer 9

thanks

Answer 10

This is an integration by parts problem. No wonder I forgot how to do it.