Question

A farmer wants to fence an area of 750,000m^2 in a rectangular field and divide it in half with a fence parallel to one of the sides of the rectangle. How can this be done so as to minimize the cost of the fence?

Answer 1

this on a test go away

Answer 2

??? It's homework

Answer 3

show ur attempt please

Answer 4

A=area =(L)(W)
750 000=(L)(W)
W=750 000/L
P=perimeter=3L(2W)
P=3L+2(750 000/L)
Am I doing this correctly?

Answer 5

@rational

Answer 6

can you sketch the rectangular field you have in mind while setting up those equations

Answer 7

Oh I think I got it.
So I differentiated the perimeter equation and then set it to 0 and got
0=3L^2-1 500 000
Then after I isolate the L and got sqrt500 000. It then been simplified as 500sqrt2=L

Answer 8

looks good to me

Answer 9

Okay thanks for checking! :D

Answer 10

http://www.wolframalpha.com/input/?i=minimize+3L%2B2%28750000%2FL%29%2C+L%3E0