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OpenStudy (anonymous):
OpenStudy (anonymous):
theorem?
OpenStudy (anonymous):
is it?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
and which one should be?
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OpenStudy (anonymous):
google it
OpenStudy (anonymous):
i can't
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@iGreen
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OpenStudy (anonymous):
First thing is to draw the figures.
We have a triangle ABC where AB does not equal BC.
BD is the median splitting AC in two equal parts
If BD were perpendicular to AC then angle BDC and angle BDA would be right angles.
If they were right angles then BD^2+CD^2 would equal BC^2
and AD^2+BD^2 would equal AB^2
and since BD=BD and AD=DC then BC and BA would be equal but we are told that AB is not congruent to BC therefore they can't be right triangles and therefore angle BDC and angle BDA are not right angles.
Since they are not right angles, the lines(segment) BD and AC are not perpendicular. QED
OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
got it or not?
OpenStudy (anonymous):
google it
OpenStudy (anonymous):
do ask your teacher or tutor
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OpenStudy (anonymous):
my teacher
OpenStudy (anonymous):
I'll search it when I go home
OpenStudy (anonymous):
SAS. The line in the middle is congruent to itself, then corresponding right angles, and if it's in the middle, then it splits the bottom in half, making both part congruent as well.