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!!!!!!!!!!!!!!!!MEDALS!!!!!!!!!!!!!!!!!!!! In a sample of 60 households, the mean number of cups of milk drank in June was 82. In a much larger study, the standard deviation was determined to be 68. For the following questions, assume the population standard deviation is the same.
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Margin of error=\[1.96\times \frac{ \sigma }{ \sqrt{n} }\]
1.) Solve for the 95% confidence interval for the mean cups of milk drank in June? Please show all work and explain your steps for full credit
2.) Explain the difference of how you would solve this if you wanted a 98% confidence interval instead.
@dan815 @nincompoop
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