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Mathematics 20 Online
OpenStudy (anonymous):

Which equation is graphed here? http://static.k12.com/calms_media/media/1312500_1313000/1312639/1/5634cf4cc78c5f954e9151076931e1346ad3a658/HS_A1G2_S1_07_08_ART1.jpg A. y-3= -2/3(x+1) B. y-4= -3/2(x+2) C. y-1= -3/2(x+3) D. y+1= -2/3(x-3)

OpenStudy (ashes.boom):

Can i help?

OpenStudy (ashes.boom):

@a7x_forever

OpenStudy (anonymous):

@Ashes.boom yees can you help me with this one?

OpenStudy (ashes.boom):

Yep there are a few ways we could do this, you could put each equation into standard form and see if one of them matches the graph or we could make an equation from the graph and see if it matches to one of the answers. Which would you prefer?

OpenStudy (anonymous):

make an equation from the graph

OpenStudy (ashes.boom):

Okay do you know where to start?

OpenStudy (ashes.boom):

I like to start with finding the y intercept can you find it

OpenStudy (anonymous):

one

OpenStudy (ashes.boom):

yep now you can find the slope by using the y intercept as one of your points... do you know the equation for that?

OpenStudy (ashes.boom):

Btw i might have to leave in a little bit because my class is starting but i will try to help

OpenStudy (anonymous):

the problem I really have is finding the slope itself.

OpenStudy (ashes.boom):

\[slope = y2 - y1/x2 - x1\]

OpenStudy (ashes.boom):

So you find any two points that the line intersects with okay and each point is (x, y) so you take the first point and label it 1 and the next and label it 2 so you get x and y from the first point and x and y from the second point

OpenStudy (ashes.boom):

does that make sense?

OpenStudy (anonymous):

yes I actually figured it out it is B haha but thank you for helping

OpenStudy (ashes.boom):

okay cool haha no problem

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