Question

Calculate how many moles of Fe+2(aq) were present in the conical flask.

Answer 1

\[MnO _{4^{-}}(aq) + 8H ^{+}(aq)+ 5Fe ^{2+}(aq)=Mn ^{2+}(aq)+ 5Fe ^{3+}(aq)+8H _{2}O(aq)\]

Answer 2

there are 0.04 moles of MnO4-

Answer 3

Were all reactants used up completely, without anything left over?