A golf ball mass of 0.045kg is hit off the tee at a speed of 38m/s. The golf club was in contact with the ball for 3.90*10^-3 s.
a) Find the impulse imparted to the golf ball.
b) Find the average force exerted on the ball by the golf club.

Question

A golf ball mass of 0.045kg is hit off the tee at a speed of 38m/s. The golf club was in contact with the ball for 3.90*10^-3 s.
a) Find the impulse imparted to the golf ball.
b) Find the average force exerted on the ball by the golf club.

anonymous · Answer

For part a), the impulse (left side of the equation) equals the change in momentum

$$\color{green}{\vec{F}\Delta t = m \Delta \vec{v}}$$

anonymous · Answer

So, that would be 
the normal force mgt=mv
(0.045kg)(9.8m/s)93.90*10^-3s)=(0.045kg)(38m/s)