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OpenStudy (anonymous):
A golf ball mass of 0.045kg is hit off the tee at a speed of 38m/s. The golf club was in contact with the ball for 3.90*10^-3 s. a) Find the impulse imparted to the golf ball. b) Find the average force exerted on the ball by the golf club.
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OpenStudy (anonymous):
For part a), the impulse (left side of the equation) equals the change in momentum \[\color{green}{\vec{F}\Delta t = m \Delta \vec{v}}\]
OpenStudy (anonymous):
So, that would be the normal force mgt=mv (0.045kg)(9.8m/s)93.90*10^-3s)=(0.045kg)(38m/s)
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