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Chemistry 17 Online
OpenStudy (cagliero423):

Can someone help me with calculating the number of moles? I just did an experiment for Chemistry on titration and I'm lost with the lab questions.

OpenStudy (cagliero423):

1. Write the balanced equation for the reaction of acetic acid ( ) and sodium bicarbonate ( ). What type of reaction(s) took place? 2. Calculate the number of moles of that were required to neutralize the in the vinegar. 3. Calculate the molarity of the vinegar sample. (Don’t forget to convert mL to L.) 4. Calculate the number of grams of in the vinegar. 5. Calculate the percent of acetic acid in the vinegar. (The density of vinegar is 1.002 g/ml.) 6. Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer. 7. What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution? Those are my questions, I have already answered number 1.

OpenStudy (cuanchi):

Calculate the number of moles of sodium bicarbonate that were required to neutralize the acetic acid in the vinegar. we need to know how many mL of sodium bicarbonate and the concentration of the sodium bicarbonate that you used to neutralize the vinegar

OpenStudy (cuanchi):

3. Calculate the molarity of the vinegar sample. (Don’t forget to convert mL to L.) we need to know the volume of vinegar that you used

OpenStudy (cagliero423):

okay my average use of the sodium bicarbonate was 16.33mL and the volume of the CH3COOH was 9.86mL

OpenStudy (cuanchi):

The concentration of sodium bicarbonate?

OpenStudy (cagliero423):

1.14 M

OpenStudy (cuanchi):

the number of moles of acetic in the vinegar sample is going to be equal to the number of moles in the amount of sodium bicarbonate that you has used n= M x V(L) number of moles is equal to the molarity times the volume in liters

OpenStudy (cagliero423):

So i multiply 1.14 by 9.86(after I convert it to L)?

OpenStudy (cuanchi):

no!!!! 1.14 x 0.01633 L=

OpenStudy (cagliero423):

Ohhh okay so my answer would be 0.0186?

OpenStudy (cuanchi):

ok, now with this number of moles you have to calculate the molarity in your vinegar sample

OpenStudy (cagliero423):

Okay how do I do that

OpenStudy (cuanchi):

you have to divide this number of moles by the volume of the vinegar in liters

OpenStudy (cagliero423):

Okay so 0.00186/.00986=1.886

OpenStudy (cuanchi):

good! that is the answer for the question 3

OpenStudy (cagliero423):

Okay(: I think I can figure out the rest with that, thank you so much it helped a lot.

OpenStudy (cuanchi):

no problem

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