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medal and fan the first term of an arithmetic sequence is 2 and the fourth term is 11. find the sum of the first 50 terms.
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what are the choices
3775
i dont have any
okay give me a sec ok
The nth number in an arithmetic sequence = a+(n-1)d where a is the first term and d is the difference The sum of the first n numbers in an A.P. is n/2(a+nth number)
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\[\sum _{n=1}^{50} (3 n-1)=3775 \]
Robtobey i think that's right as well that's what i got @Data_LG2
awesome. thanks guys! everyone medal each other for a job well done! lol
what was the answer
the 3775
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some one medal Jessmitz
From the Mathematica program: Table[ 3n - 1, {n, 6} ]\[\{2,5,8,11,14,17\} \]
i was right awwwwwww yaaaa
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