Question

@HelpMePlease Find the first,Fourth, and Eighth terms of the sequence
A(n)=-3*2 ^n-1
a. -6 -48 -768
b -3 -24 -384
c 1 -216 -276 -279,936
d -12 -96 -1,536

Answer 1

first term can be found by replacing n with 1
4th term can be found by replacing n with 4
8th term can be found by replacing n with 8

Answer 2

yA

Answer 3

I tryed that i cant find the answer

Answer 4

\[A(n)=-3 \cdot 2^n-1\]
replace n with 1
\[A(1)=-3 \cdot 2^1-1 \\ A(1)=-3 \cdot 2-1 \\ A(1)=-6-1 \\ A(1)=-7\]
I see the problem now...
-7 isn't an option for the 1st term

Answer 5

Or you sure you entered in the correct expression for A(n)?

Answer 6

maybe you meant A(n)=-3*2^(n-1)?

Answer 7

thats what i said bro

Answer 8

if so then you would have this
\[A(n)=-3 \cdot 2^{n-1}\]

Answer 9

no it isn't you had -3*2^n-1

Answer 10

which means
\[A(n)=-3 \cdot 2^n-1\]

Answer 11

anyways
if you mean A(n)=-3*2^(n-1)
\[A(n)=-3 \cdot 2^{n-1}\]

Answer 12

replace n with 1
can you tell me what you get as the output

Answer 13

@xo_kansasprincess_xo

Answer 14

keep in mind a^0=1
when a doesn't equal 0

Answer 15

let me know when you have evaluated
\[A(1)=-3 \cdot 2^{1-1}\]
and I will check it for you

Answer 16

@Poppy_leelee14

Answer 17

Mathway.com

Answer 18

if you need help evaluating it can you please tell me where you are having trouble?

Answer 19

like 1-1 =?

Answer 20

when you have 1 apple and you decide to eat that apple
you have how many apples left?

Answer 21

so what would the answer be

Answer 22

have you evaluated
\[-3 \cdot 2^{1-1} \text{ yet }\]

Answer 23

I was trying to help you but you haven't responded to me

Answer 24

first do the 1-1

Answer 25

yah cause i dont get it and i dont want to look like a ideat

Answer 26

you can do 1-1 though

Answer 27

like if you have exactly 1 dollar and you give that dollar away
then how many dollars do you have

Answer 28

1-1=0

Answer 29

yes you did part of it! :)
\[A(1)=-3 \cdot 2^{1-1}=-3 \cdot 2^0\]
and I told you what a^0 was
for any number a that isn't 0

Answer 30

what is 2^0 ?

Answer 31

would u mind helping me on google please

Answer 32

@freckles did u get my pm

Answer 33

I think it is easier for me to use OpenStudy

Answer 34

o okay

Answer 35

i just did not want to have every one see how dum i am

Answer 36

No one thinks you are dumb.

Answer 37

This is a learning site.
That is all anyone expects anyone to be doing here.

Answer 38

i do because people come to me for help and i am in need of help