Find finial temperature when a 25.0g piece of iron at 84.0C is placed into 75.0 grams of water at 20.0C

So the specific heat for iron is 450 and the specific heat for water is 4186

Im having trouble on plugging the numbers in for this question and this question is an equilibrium problem which is Qgain=Qlist
M Cp (tfinial-tintial)= M Cp (tintial-tfinal)

Question

Find finial temperature when a 25.0g piece of iron at 84.0C is placed into 75.0 grams of water at 20.0C

So the specific heat for iron is 450 and the specific heat for water is 4186

Im having trouble on plugging the numbers in for this question and this question is an equilibrium problem which is Qgain=Qlist 
M Cp (tfinial-tintial)= M Cp (tintial-tfinal)

aaronq · Answer

$\sf \huge \sf -Q_{lost}=Q_{gained}$

$\sf \huge -[\underbrace{m *C_p (\color{red}{T_f}-T_i)}_{metal }]=\underbrace{m *C_p (\color{red}{T_f}-T_i)}_{water}$