Question

Rule for the nth term of a_16=52, d=5?

Answer 1

\[a_n = a_1 + (n - 1)d\]

Answer 2

Can you explain how to find that? I have a bunch like it

Answer 3

\[a_16 = 52 ~~(given)\]
also
\[a_{16} = a_1 + (n - 1)d\]
so
\[52 = a_1 + (16 - 1)d\]

Answer 4

Is that top formula just the general one????

Answer 5

and what about d=5?

Answer 6

the top formula is a general one....
plug d = 5 in the equation

Answer 7

so \[16=a_1+(n-1)5\]

Answer 8

nah nah.....it would be
\[52 = a_1 + (16 - 1)5\]
get a_1 and plug it in general equation for nth term

Answer 9

Wait so what's the answer then?

Answer 10

oh nvm I see.. I thought u said that the general equation was the answer lol

Answer 11

on solving tht equation u will get a_1 = -23
so for nth term
\[a_n = a_1 + (n - 1)d\]
plug a_1 and d

Answer 12

\[a_n=-23+(n-1)5\] ?

Answer 13

Well wouldn't it actually be
\[a_n=-28+5n\] ??

Answer 14

yup....:))

Answer 15

Cool thank you very much!

Answer 16

yw