Thermal stability question
why is it that for formation reactions the lower the enthalpy value the higher the thermal stability? (vice versa) and for decomposition reactions, when the lower the enthalpy value the lower the thermal stability? (vice versa)
@Hoslos
Enthapy change is the energy absorbed by reactants to form products. If this value is small, it means that the reaction is spontaneous and when this happens, the product is able to form a very strong structure against temperature, giving it high thermal stability. Whereas reaction that will need higher input of energy (enthalpy change) would also need much higher energy to form very strong structures of products. As ror decomposition reactions, the statement is true. Just think about gases. They need a low energy input to decompose and when this happens, gases as elements or in their standard states are very volatile and weak in structure ( low thermal stability) while if you are to decompose CaCO3, the enrgy input is higher and the structure of the products is stronger (CO2 and CaO).
perfect thank you :)
We are good!
oh wait i have a question about this
i know that when it says higher or lower the negative values its the the enthalpy changes... so lets say given -100000 and -100 so when it says lower the negative value is that -100000 or -100?
if its lower does it mean its more negative?
The first one is the lower value, which means more negative.
s wich means it has a higher thrmal stability right?
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