If the parent function f(x) = x2 is modified to g(x) = 2x2 + 1, which statement is true about g(x)?
It is an even function.
It is an odd function.
It is both an even and an odd function.
It is neither an even nor an odd function.
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OpenStudy (anonymous):
f(x)=x^2 is modified to g(x)=2x^2+1
OpenStudy (lexi724):
A function f(x) is an even function if f(-x) = f(x). In other words, replacing x with -x doesn't modify the function.
A function f(x) is an odd function if f(-x) = -f(x). In other words, replacing x with -x is identical to the equation obtained after multiplying each term by -1.
OpenStudy (anonymous):
I dont see no -x
OpenStudy (anonymous):
...
OpenStudy (lexi724):
its basically the proof tho
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OpenStudy (anonymous):
So is it neither or not
OpenStudy (lexi724):
maybe @iGreen can be of some assistance im terrible at explaining things
OpenStudy (anonymous):
I think its even cause it stretches out
OpenStudy (anonymous):
It has to be even green
OpenStudy (anonymous):
and it is even
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