Using the equation 2H2 + O2 --> 2 H2O, if 192 g of O are produced, how many grams of hydrogen must react with it? Help me understand how to do this?
\(\LARGE 2H_2+O_2\to2H_2O\) 2 moles hydrogen gas reacts with 1 mol oxygen gas to produce 2 moles of water The first thing I notice is that there's something wrong with the question. You know that 192 grams of O are produced. But O is not the product of this reaction right? Shouldn't it be 192 grams of \(\LARGE H_2O\) ?
or is it 192 g of O is used in the used in the reaction?
No my question said if 192 g of oxygen are produced, how many grams of hydrogen must react with it?
its stoichiometry, mass/mass and % yield
Ah well seemed odd, but it's very simple. You start with calculating the amount of moles \(O_2\) you have. 1 mol \(O_2\) is 32.998 grams (because the molecular weight of O is 15.999, you can check this on a periodic tabel) Now you convert 192 gram to mole by simply dividing the 192 grams by the weight of 1 mol. so 192/31.998
And that's the answer? Wow I had no clue it was this simple. my teacher described it totally different.
I get 6 but my answers are 36, 12, 48, and 24
Yea that's not the answer yet, the site crashed and wouldn't reload, sorry for that. You know you have 6 moles of \(O_2\) now you need to know how many moles of \(O_2\) react with \(H_2\) I kinda already gave the answer to that in my first reply.
1mole of O2 reacts with 2 moles of H2?
Hey im sorry I couldn't get on for some reason. 1 mole of O2 will react with 2 moles of h2 right?
the whole wording of the question is incorrect. You can't produce \(O_2\) because it is a \(reactant\). You can \(use\) \(O_2\), and produce water, but the general principle is still balanced reactions produce useful ratios
Im sorry, that's just what my paper said. I struggle with finding stuff like this. I can do the math, but I have a hard time figuring out what to use in the math
Sorry the site wasn't working anymore yesterday. 1 mole of O2 reacts with 2 moles of H2 in this reaction, that's correct. According to this ratio, 6 moles of O2 will react with 6*2=12 moles of H2. So the last thing you have to do is calculate the amount of grams H2 which equals 12 moles. For hydrogen this is very simple as 1 mole H roughtly weighs 1 gram. So 1 mole H2 will weigh 2 gram. We have 12 moles so that'd equal 24 grams of hydrogen gas.
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