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Mathematics 16 Online
OpenStudy (18jonea):

. Use the Pythagorean theorem to solve for x.

OpenStudy (vlery):

where's the triangle?

OpenStudy (vlery):

also think of the P. Theorem as this: |dw:1427903122392:dw| A^2+B^2=C^2

OpenStudy (18jonea):

so what would you get

OpenStudy (vlery):

The square of any squareroot will just be the number left because they'll just cancel each other out then 7^2 is 49; 49+14=63 and since you can't squareroot that for a perfect number you keep it as \[\sqrt{63}\]

OpenStudy (18jonea):

thats not any of my choices

OpenStudy (anonymous):

\[x=\sqrt{7^2-\sqrt{14}^2}=\sqrt{35} \]

OpenStudy (18jonea):

thanks! @robtobey

OpenStudy (anonymous):

Your welcome.

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