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. Use the Pythagorean theorem to solve for x.
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where's the triangle?
also think of the P. Theorem as this: |dw:1427903122392:dw| A^2+B^2=C^2
so what would you get
The square of any squareroot will just be the number left because they'll just cancel each other out then 7^2 is 49; 49+14=63 and since you can't squareroot that for a perfect number you keep it as \[\sqrt{63}\]
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thats not any of my choices
\[x=\sqrt{7^2-\sqrt{14}^2}=\sqrt{35} \]
thanks! @robtobey
Your welcome.
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