Choose the correct rewriting of this algebraic fraction and give the exclusion represented by your choice. 4y (8y + 24) –1 = y ≠
@StudyGurl14
you may want to retype the question, as there doesn't appear to be a fraction
Answer choices for #1: 2y/2y+3 or y/(2)(y+3) #2: -3 or 3
Is that better? @campbell_st
takes a fraction... so looking at the 2 terms in the denominator... do 2y and 3 have a common factor...?
No
can I check is the fraction 1. \[\frac{4y}{8y + 24} -1 \]
What?
well the original fraction you posted has -1 at the end...
No, that's an exponent.
ok... so its \[4y (8y + 24)^{-1}\]
which can be written as \[\frac{4y}{8y + 24}\] 4 is a common factor... so divide every term by 4 what do you get...?
y/2y+6
great.... and is ther a common factor in the denominator..?
2?
great so then the factored form is a little weird but its the 2nd of your choices... so looking at y + 3 what value of y makes the expression zero..?
Dude I have no idea.
well solve this Dudette y + 3 = 0
the answer you get will be the restriction for the denominator
-3
@campbell_st
correct... so now you have the solution.... restrictions in fractions are the value(s) that make the denominator zero.... so looking at the original question you needed to solve 8y + 24 = 0 its the same answer as the simplified version.
That doesn't make sense
@superdavesuper
ok.... tell be what happens when you enter this into a calculator \[2 \div 0 =\]
0
no actually pick up a calculator and do it
Lol no. I don't have time for this. You're making me do extra work that is totally unnecessary.
you answer is to the problem \[0 \div 2 = 0\]
well it is necessary as its fundamental to the questions you are asking.
Not really. I'm not gonna do extra work when I have enough as it is.
is a simple task... use a calculator http://web2.0calc.com/ here is an online on... tell me what happens with the calculation \[2 \div 0 =\]
@nehemiah2
Nah
y not equal to -3
@ribhu English, please.
y would not be equal to -3
Soooo what's that mean?
that's a solution you found a lot earlier..
what do u want exactly?
Okay, what about the other one then? @ribhu obviously I want the answer.
you have found both answers... you just need to go back and read thinks... remember Open study is about helping your understanding... and not for providing answers...
@nehemiah2
I'm not gonna get on Facebook, @ribhu
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