Potassium chlorate decomposes according to the following balanced equation: 2 KClO3 --> 2 KCl +3O2 How many grams of oxygen gas would be produced if 23.0 g of potassium chlorate react? Please help me understand how to complete, very poor with stoichiometry.
hm what is the ratio between KClO3 and O2 ?
2:3?
yep
so now lest find the mole of KClO3
you have the mass given and you can calculate molecular mass from periodic table
so use the values in this formula mole = mass / molecular mass and find the mole i hope u r familiar with this formula?
yes so itd be 23/123? or the other way around?
that is the right way so whats the answer u got?
0.187
mkay so that is your mole and now use the ratio and find mole of O2 2 :3 is the ratio as u said now 2 - the mole you just got 3 - unknown mole now do cross multiplication (as in math) and find the unknown mole
0.281
okay so now use this mole and again use mole formula mole = mass / molecular mass so now rearrange the formula to get mass and then find mass
0.002?
no that doesnt sound correct show me your working
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