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Chemistry 19 Online
OpenStudy (anonymous):

Potassium chlorate decomposes according to the following balanced equation: 2 KClO3 --> 2 KCl +3O2 How many grams of oxygen gas would be produced if 23.0 g of potassium chlorate react? Please help me understand how to complete, very poor with stoichiometry.

OpenStudy (somy):

hm what is the ratio between KClO3 and O2 ?

OpenStudy (anonymous):

2:3?

OpenStudy (somy):

yep

OpenStudy (somy):

so now lest find the mole of KClO3

OpenStudy (somy):

you have the mass given and you can calculate molecular mass from periodic table

OpenStudy (somy):

so use the values in this formula mole = mass / molecular mass and find the mole i hope u r familiar with this formula?

OpenStudy (anonymous):

yes so itd be 23/123? or the other way around?

OpenStudy (somy):

that is the right way so whats the answer u got?

OpenStudy (anonymous):

0.187

OpenStudy (somy):

mkay so that is your mole and now use the ratio and find mole of O2 2 :3 is the ratio as u said now 2 - the mole you just got 3 - unknown mole now do cross multiplication (as in math) and find the unknown mole

OpenStudy (anonymous):

0.281

OpenStudy (somy):

okay so now use this mole and again use mole formula mole = mass / molecular mass so now rearrange the formula to get mass and then find mass

OpenStudy (anonymous):

0.002?

OpenStudy (somy):

no that doesnt sound correct show me your working

OpenStudy (anonymous):

|dw:1427923430398:dw|

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