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Mathematics 75 Online
OpenStudy (hulkart):

The half life of Pb-210 is 22 years. A decayed animal shows 48% of the original Pb-210 remains; how long has the animal been deceased to the nearest tenth of a year? 0.01 years 23.3 years 22.29 years 0.04 years

OpenStudy (asnaseer):

Do you know how to represent half-life as an equation?

OpenStudy (hulkart):

no

OpenStudy (asnaseer):

Does this equation look familiar to you at all?\[A=A_0\times\left(\frac{1}{2}\right)^{\frac{t}{h}}\]

OpenStudy (hulkart):

so can you plug it in?

OpenStudy (asnaseer):

You need to first understand this equation - have you seen anything like it before?

OpenStudy (hulkart):

no

OpenStudy (asnaseer):

OK - let me try to explain it to you...

OpenStudy (asnaseer):

When we have some substance that decays according to the half life rule then we have: 1. \(A_0\) represents the initial amount of a substance 2. \(h\) represents the half life of the substance (in your question we have \(h=22\) years) 3. \(t\) represents the amount of time that has elapsed (in your question this would be measured in years) 4. \(A\) represents the amount of substance left after time \(t\) has elapsed Does this make sense to you?

OpenStudy (hulkart):

kinda...

OpenStudy (asnaseer):

In your question the substance being talked about is Pb-220 (a form of lead). So \(A\) represents the amount of this lead left after \(t\) years have elapsed. If we take your question where we have \(h=22\) we get:\[A=A_0\times\left(\frac{1}{2}\right)^{\frac{t}{22}}\]Following so far?

OpenStudy (hulkart):

don't worry I can continue on my own

OpenStudy (asnaseer):

great - why don't you let me know when you have an answer and I will check it for you. Just ping me when you are ready.

OpenStudy (hulkart):

ok...

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