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Exponential equation (log): 625^x=1/√5 Please explain the process for how to solve this!
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First note that \(625=5^4\). Then also notice that \(\frac{1}{\sqrt{5}}=\frac{1}{5^{0.5}}=5^{-0.5}\) So your equation reduces to:\[(5^4)^x=5^{-0.5}\]Which you should be able to solve without using logs.
You're amazing, thanks so much. Only..how do I solve from there? :)
Nevermind! I got it now.
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