My answers and the question are both in the image
As always will give you, your medal for helping me :]

Question

studygurl14 · Answer

sin A, tan A, and cos B are all incorrect. Did you solve for the missing side using the Pythagorean theorem?

anonymous · Answer

@StudyGurl14 all my answers are all wrong that's why I need someone to check and tell me what I did wrong so I can redo it.

anonymous · Answer

and If i did it correctly the missing side is 2?

anonymous · Answer

@jeweaver6895

studygurl14 · Answer

The missing side is not 2.
Pythaogrean Theorem:
$\Large a^2+b^2=c^2$

c = 2, a = 1. Solve for b.

anonymous · Answer

Ohhhh Okay I see and yeah I know what the Pythaogrean Theorem is but I put the equation all wrong
Okay so is it: 1 then?

anonymous · Answer

@StudyGurl14

studygurl14 · Answer

No, it's not 1.

studygurl14 · Answer

$\Large a^2+b^2=c^2\rightarrow (1)^2 + b^2 = (2)^2\rightarrow b^2 = 4 - 1\rightarrow b=?$

anonymous · Answer

Oops I forgot about the (^2) okay so its 3

anonymous · Answer

@jim_thompson5910 @johnweldon1993 @Babynini

jim_thompson5910 · Answer

you should have $\Large b^2 = 3$. So what is the value of b itself?

anonymous · Answer

Do I find the sqrt of 3? sorry if I'm a bit slow this is the hardest geometry I've done so far so I don't get it so much.

jim_thompson5910 · Answer

correct, b is sqrt(3)

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