Question

A block is placed on an inclined plane. The static coefficient of friction between the block and the plane is .300. What is the maximum angle the plane can have without the block starting to slide?

Answer 1

Ket the angle between the inclined plane n horizontal plane is theta

Answer 2

*let

Answer 3

Let the mass of the block is m

Answer 4

So weight of mass m =mg

Answer 5

Component of weight mg along inclined plane=mg*sin theta

Answer 6

friction(.300) + mgsin(theta) =ma?

Answer 7

Component of weight mg perpendicular to the inclined plane=mg*cos theta

Answer 8

oh so .300 + mgcos(theta)=0

Answer 9

Acceleration a=0 in ur equation. Because the block is static

Answer 10

yes i forgot that

Answer 11

So
Frictional force=mg*sin theta
Right?

Answer 12

so .300=mgcos(theta)

Answer 13

yes

Answer 14

No

Answer 15

mgcos(theta)

Answer 16

Frictional force=coefficeint of static friction*mg*cos theta

Answer 17

R=mg*cos theta

Answer 18

what is r?

Answer 19

Frictional force=0.3*mg*cos theta

Answer 20

R is a force acting on the block by the inclined plane

Answer 21

oh ok

Answer 22

mg*cos theta
Is a force acting on the inclined plane by the block

Answer 23

so how do you get a value if you only have 1 to plug in

Answer 24

Ok
0.3*mg*cos theta=mg*sin theta
Theta=?

Answer 25

Anyway i m frm an android cell phone

Answer 26

So its not possible to draw

Answer 27

Can u draw it

Answer 28

ok ill try