Mathematics
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OpenStudy (anonymous):
solve for x: x^3-10x^2+24x
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OpenStudy (anonymous):
u can divide for x
OpenStudy (anonymous):
it will be x^2-10x+24
OpenStudy (anonymous):
but u must writing \[x \neq 0\]
OpenStudy (anonymous):
it need to be an equation, to get the value for x
OpenStudy (lexi724):
messaging you
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OpenStudy (anonymous):
D = b^2 - 4ac
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
@Ziferot
to apply for quadratic formula you need to make the expression =0
OpenStudy (lexi724):
no problem @Jake_Litt and What? @lall
OpenStudy (anonymous):
@lall ok x^2-10x+24=0
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OpenStudy (anonymous):
thats batter??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
it doesnt matter
OpenStudy (anonymous):
do you know\[ \frac{ d }{ dx }(x ^{2}-10x+24)=\pm \sqrt{10^{2}-4(1)24}\]
@Ziferot
OpenStudy (anonymous):
???
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OpenStudy (anonymous):
new for you?
i was just sharing knowledge
just solve it
OpenStudy (anonymous):
no
OpenStudy (anonymous):
i have a very good knowledge in math and high math , but bad knowledge in English )))
OpenStudy (anonymous):
you get x=6,4
OpenStudy (anonymous):
solving it by quadratic formula, you get the same result
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OpenStudy (anonymous):
I haven't resolve it ))) i'm on work)))
OpenStudy (anonymous):
but you don't need the quadratic formula
OpenStudy (anonymous):
yes this can be done by splitting method also
OpenStudy (anonymous):
+ yeah,his right )
OpenStudy (anonymous):
see this @Ziferot \[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
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OpenStudy (anonymous):
\[2ax+b=\pm \sqrt{b ^{2}-2ac}\]
OpenStudy (anonymous):
\[\frac{ d }{ dx }(ax ^{2}+bx+c)=\sqrt{D}\]
OpenStudy (anonymous):
@Ziferot
OpenStudy (lexi724):
he already has the answer guys
OpenStudy (anonymous):
have you seen it before????
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OpenStudy (anonymous):
its not correct
OpenStudy (anonymous):
how
OpenStudy (anonymous):
see it again
OpenStudy (lexi724):
in his inbox its not posted here