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Mathematics 9 Online
OpenStudy (anonymous):

A book on Olympiad Inequalities inside---> checkout!

OpenStudy (anonymous):

OpenStudy (rational):

looks like a nice read

OpenStudy (anonymous):

Yes , much knowledge inside

OpenStudy (mayankdevnani):

thanks for sharing with us !

OpenStudy (mayankdevnani):

its better for RMO and INMAO

OpenStudy (anonymous):

even for IIT advance

OpenStudy (mayankdevnani):

nope

OpenStudy (mayankdevnani):

i have syllabus , there is nothing use in IIT ADVANCE

OpenStudy (anonymous):

Well , Inequality and sequences and series is there

OpenStudy (anonymous):

and the problems or 4-5 lines maximum

OpenStudy (mayankdevnani):

but do you know what type of inequality is there (level) like WAVY CURVE method and more

OpenStudy (mayankdevnani):

http://jeeadv.iitm.ac.in/taxonomy/term/50

OpenStudy (mayankdevnani):

END THE DISCUSSION HERE !

OpenStudy (rational):

iit problems related to inequalities are simpler compared to IMO problems

OpenStudy (rational):

so you can use this textbook as an extra read while preparing for iit too there is no harm in learning more

OpenStudy (mayankdevnani):

correct ! @rational this is i want to say @No.name

OpenStudy (anonymous):

Yeah precisely :)

OpenStudy (mayankdevnani):

by the way, are you indian ? @rational

OpenStudy (anonymous):

^ ?

OpenStudy (mayankdevnani):

kya rational indian h ? main yeh pooch raha huin !

OpenStudy (anonymous):

yes i meant to say , i am asking the same question as you were asking SO, "^ ? "

OpenStudy (mayankdevnani):

what i have asked ? @No.name

OpenStudy (rational):

yes :) try this little inequality problem prove below for \(a,b,c\in \mathbb{R}\)\[\dfrac{a^2+b^2+c^2}{abc}\ge \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}\]

OpenStudy (anonymous):

First prove a^2 + b^2 + c^2 >= ab +bc +ca Then divide both by abc

OpenStudy (rational):

That will do haha!

OpenStudy (anonymous):

TP a^2 + b^2 + c^2 >= ab +bc +ca Apply AM-GM on a^2 , b^2 Similarly , yeah u got the point !!

OpenStudy (anonymous):

well any clever approach?

OpenStudy (rational):

To me what you have is a clever approach because it is neat xD

OpenStudy (anonymous):

http://www.imomath.com/index.php?options=344

OpenStudy (anonymous):

that is very hard , but just sharing

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