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Physics 23 Online
OpenStudy (anonymous):

draw the electric field around these charges. Mark where the field strength is at its strongest and determin how big it is.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Michele_Laino is it just like this|dw:1427987818137:dw|

OpenStudy (anonymous):

the question is not where it is the strongest, it is where it is the smallest

OpenStudy (anonymous):

but I dont know how to determin how big it is?

OpenStudy (michele_laino):

are the charges like-point?

OpenStudy (anonymous):

did you see my attachment?

OpenStudy (anonymous):

thats the only thing I get

OpenStudy (michele_laino):

yes!

OpenStudy (michele_laino):

ok! I consider your charge like-point. So we have to keep in mind that the electric field caused by each charge, is given by the subsequent formula: \[{\mathbf{E}} = \frac{q}{r}{\mathbf{\hat r}}\]

OpenStudy (michele_laino):

oops.. \[{\mathbf{E}} = \frac{q}{{{r^2}}}{\mathbf{\hat r}}\]

OpenStudy (michele_laino):

where q is the value of the charge, r is the distance from the charge, and \[{\mathbf{\hat r}}\] is the unit vector whose direction is the same as the direction ov the position vector \[{\mathbf{r}}\]

OpenStudy (michele_laino):

|dw:1427988620559:dw|

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